3a^2-50a+48=0

Solution for 3a^2-50a+48=0 equation:

3a^2-50a+48=0

a = 3; b = -50; c = +48;
Δ = b2-4ac
Δ = -502-4·3·48
Δ = 1924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1924}=\sqrt{4*481}=\sqrt{4}*\sqrt{481}=2\sqrt{481}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{481}}{2*3}=\frac{50-2\sqrt{481}}{6}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{481}}{2*3}=\frac{50+2\sqrt{481}}{6}
$